Optimal. Leaf size=175 \[ -\frac{a^3 \cos ^3(c+d x)}{3 d}+\frac{a^3 \cos (c+d x)}{d}-\frac{a^3 \cot ^5(c+d x)}{5 d}-\frac{2 a^3 \cot ^3(c+d x)}{3 d}+\frac{5 a^3 \cot (c+d x)}{d}+\frac{3 a^3 \sin (c+d x) \cos (c+d x)}{2 d}-\frac{25 a^3 \tanh ^{-1}(\cos (c+d x))}{8 d}-\frac{3 a^3 \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac{23 a^3 \cot (c+d x) \csc (c+d x)}{8 d}+\frac{13 a^3 x}{2} \]
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Rubi [A] time = 0.298944, antiderivative size = 175, normalized size of antiderivative = 1., number of steps used = 16, number of rules used = 7, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {2709, 3770, 3767, 8, 3768, 2635, 2633} \[ -\frac{a^3 \cos ^3(c+d x)}{3 d}+\frac{a^3 \cos (c+d x)}{d}-\frac{a^3 \cot ^5(c+d x)}{5 d}-\frac{2 a^3 \cot ^3(c+d x)}{3 d}+\frac{5 a^3 \cot (c+d x)}{d}+\frac{3 a^3 \sin (c+d x) \cos (c+d x)}{2 d}-\frac{25 a^3 \tanh ^{-1}(\cos (c+d x))}{8 d}-\frac{3 a^3 \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac{23 a^3 \cot (c+d x) \csc (c+d x)}{8 d}+\frac{13 a^3 x}{2} \]
Antiderivative was successfully verified.
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Rule 2709
Rule 3770
Rule 3767
Rule 8
Rule 3768
Rule 2635
Rule 2633
Rubi steps
\begin{align*} \int \cot ^6(c+d x) (a+a \sin (c+d x))^3 \, dx &=\frac{\int \left (8 a^9+6 a^9 \csc (c+d x)-6 a^9 \csc ^2(c+d x)-8 a^9 \csc ^3(c+d x)+3 a^9 \csc ^5(c+d x)+a^9 \csc ^6(c+d x)-3 a^9 \sin ^2(c+d x)-a^9 \sin ^3(c+d x)\right ) \, dx}{a^6}\\ &=8 a^3 x+a^3 \int \csc ^6(c+d x) \, dx-a^3 \int \sin ^3(c+d x) \, dx+\left (3 a^3\right ) \int \csc ^5(c+d x) \, dx-\left (3 a^3\right ) \int \sin ^2(c+d x) \, dx+\left (6 a^3\right ) \int \csc (c+d x) \, dx-\left (6 a^3\right ) \int \csc ^2(c+d x) \, dx-\left (8 a^3\right ) \int \csc ^3(c+d x) \, dx\\ &=8 a^3 x-\frac{6 a^3 \tanh ^{-1}(\cos (c+d x))}{d}+\frac{4 a^3 \cot (c+d x) \csc (c+d x)}{d}-\frac{3 a^3 \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac{3 a^3 \cos (c+d x) \sin (c+d x)}{2 d}-\frac{1}{2} \left (3 a^3\right ) \int 1 \, dx+\frac{1}{4} \left (9 a^3\right ) \int \csc ^3(c+d x) \, dx-\left (4 a^3\right ) \int \csc (c+d x) \, dx+\frac{a^3 \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (c+d x)\right )}{d}-\frac{a^3 \operatorname{Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,\cot (c+d x)\right )}{d}+\frac{\left (6 a^3\right ) \operatorname{Subst}(\int 1 \, dx,x,\cot (c+d x))}{d}\\ &=\frac{13 a^3 x}{2}-\frac{2 a^3 \tanh ^{-1}(\cos (c+d x))}{d}+\frac{a^3 \cos (c+d x)}{d}-\frac{a^3 \cos ^3(c+d x)}{3 d}+\frac{5 a^3 \cot (c+d x)}{d}-\frac{2 a^3 \cot ^3(c+d x)}{3 d}-\frac{a^3 \cot ^5(c+d x)}{5 d}+\frac{23 a^3 \cot (c+d x) \csc (c+d x)}{8 d}-\frac{3 a^3 \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac{3 a^3 \cos (c+d x) \sin (c+d x)}{2 d}+\frac{1}{8} \left (9 a^3\right ) \int \csc (c+d x) \, dx\\ &=\frac{13 a^3 x}{2}-\frac{25 a^3 \tanh ^{-1}(\cos (c+d x))}{8 d}+\frac{a^3 \cos (c+d x)}{d}-\frac{a^3 \cos ^3(c+d x)}{3 d}+\frac{5 a^3 \cot (c+d x)}{d}-\frac{2 a^3 \cot ^3(c+d x)}{3 d}-\frac{a^3 \cot ^5(c+d x)}{5 d}+\frac{23 a^3 \cot (c+d x) \csc (c+d x)}{8 d}-\frac{3 a^3 \cot (c+d x) \csc ^3(c+d x)}{4 d}+\frac{3 a^3 \cos (c+d x) \sin (c+d x)}{2 d}\\ \end{align*}
Mathematica [A] time = 1.63668, size = 271, normalized size = 1.55 \[ \frac{a^3 (\sin (c+d x)+1)^3 \left (6240 (c+d x)+720 \sin (2 (c+d x))+720 \cos (c+d x)-80 \cos (3 (c+d x))-2624 \tan \left (\frac{1}{2} (c+d x)\right )+2624 \cot \left (\frac{1}{2} (c+d x)\right )-45 \csc ^4\left (\frac{1}{2} (c+d x)\right )+690 \csc ^2\left (\frac{1}{2} (c+d x)\right )+45 \sec ^4\left (\frac{1}{2} (c+d x)\right )-690 \sec ^2\left (\frac{1}{2} (c+d x)\right )+3000 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )-3000 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )+304 \sin ^4\left (\frac{1}{2} (c+d x)\right ) \csc ^3(c+d x)-3 \sin (c+d x) \csc ^6\left (\frac{1}{2} (c+d x)\right )-19 \sin (c+d x) \csc ^4\left (\frac{1}{2} (c+d x)\right )+6 \tan \left (\frac{1}{2} (c+d x)\right ) \sec ^4\left (\frac{1}{2} (c+d x)\right )\right )}{960 d \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )^6} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.095, size = 293, normalized size = 1.7 \begin{align*}{\frac{5\,{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{8\,d \left ( \sin \left ( dx+c \right ) \right ) ^{2}}}+{\frac{5\,{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{5}}{8\,d}}+{\frac{25\,{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{3}}{24\,d}}+{\frac{25\,{a}^{3}\cos \left ( dx+c \right ) }{8\,d}}+{\frac{25\,{a}^{3}\ln \left ( \csc \left ( dx+c \right ) -\cot \left ( dx+c \right ) \right ) }{8\,d}}-{\frac{{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{d \left ( \sin \left ( dx+c \right ) \right ) ^{3}}}+4\,{\frac{{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{d\sin \left ( dx+c \right ) }}+4\,{\frac{{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{5}\sin \left ( dx+c \right ) }{d}}+5\,{\frac{{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{3}\sin \left ( dx+c \right ) }{d}}+{\frac{15\,{a}^{3}\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2\,d}}+{\frac{13\,{a}^{3}x}{2}}+{\frac{13\,{a}^{3}c}{2\,d}}-{\frac{3\,{a}^{3} \left ( \cos \left ( dx+c \right ) \right ) ^{7}}{4\,d \left ( \sin \left ( dx+c \right ) \right ) ^{4}}}-{\frac{{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{5}}{5\,d}}+{\frac{{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}-{\frac{{a}^{3}\cot \left ( dx+c \right ) }{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.7904, size = 338, normalized size = 1.93 \begin{align*} -\frac{20 \,{\left (4 \, \cos \left (d x + c\right )^{3} - \frac{6 \, \cos \left (d x + c\right )}{\cos \left (d x + c\right )^{2} - 1} + 24 \, \cos \left (d x + c\right ) - 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) + 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )} a^{3} - 120 \,{\left (15 \, d x + 15 \, c + \frac{15 \, \tan \left (d x + c\right )^{4} + 10 \, \tan \left (d x + c\right )^{2} - 2}{\tan \left (d x + c\right )^{5} + \tan \left (d x + c\right )^{3}}\right )} a^{3} + 16 \,{\left (15 \, d x + 15 \, c + \frac{15 \, \tan \left (d x + c\right )^{4} - 5 \, \tan \left (d x + c\right )^{2} + 3}{\tan \left (d x + c\right )^{5}}\right )} a^{3} + 45 \, a^{3}{\left (\frac{2 \,{\left (9 \, \cos \left (d x + c\right )^{3} - 7 \, \cos \left (d x + c\right )\right )}}{\cos \left (d x + c\right )^{4} - 2 \, \cos \left (d x + c\right )^{2} + 1} - 16 \, \cos \left (d x + c\right ) + 15 \, \log \left (\cos \left (d x + c\right ) + 1\right ) - 15 \, \log \left (\cos \left (d x + c\right ) - 1\right )\right )}}{240 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.28919, size = 738, normalized size = 4.22 \begin{align*} -\frac{360 \, a^{3} \cos \left (d x + c\right )^{7} - 2392 \, a^{3} \cos \left (d x + c\right )^{5} + 3640 \, a^{3} \cos \left (d x + c\right )^{3} - 1560 \, a^{3} \cos \left (d x + c\right ) + 375 \,{\left (a^{3} \cos \left (d x + c\right )^{4} - 2 \, a^{3} \cos \left (d x + c\right )^{2} + a^{3}\right )} \log \left (\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) \sin \left (d x + c\right ) - 375 \,{\left (a^{3} \cos \left (d x + c\right )^{4} - 2 \, a^{3} \cos \left (d x + c\right )^{2} + a^{3}\right )} \log \left (-\frac{1}{2} \, \cos \left (d x + c\right ) + \frac{1}{2}\right ) \sin \left (d x + c\right ) + 10 \,{\left (8 \, a^{3} \cos \left (d x + c\right )^{7} - 156 \, a^{3} d x \cos \left (d x + c\right )^{4} - 40 \, a^{3} \cos \left (d x + c\right )^{5} + 312 \, a^{3} d x \cos \left (d x + c\right )^{2} + 125 \, a^{3} \cos \left (d x + c\right )^{3} - 156 \, a^{3} d x - 75 \, a^{3} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{240 \,{\left (d \cos \left (d x + c\right )^{4} - 2 \, d \cos \left (d x + c\right )^{2} + d\right )} \sin \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24863, size = 373, normalized size = 2.13 \begin{align*} \frac{6 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} + 45 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} + 50 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 600 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 6240 \,{\left (d x + c\right )} a^{3} + 3000 \, a^{3} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right ) - 2580 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - \frac{320 \,{\left (9 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 12 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 9 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 4 \, a^{3}\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 1\right )}^{3}} - \frac{6850 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 2580 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 600 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 50 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 45 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 6 \, a^{3}}{\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5}}}{960 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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